What is the load center length for a branch circuit with noncontinuous loads of 20A at 60' and 50A at 125'?

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Multiple Choice

What is the load center length for a branch circuit with noncontinuous loads of 20A at 60' and 50A at 125'?

Explanation:
To determine the load center length for a branch circuit with noncontinuous loads, it is important to calculate the weighted average based on the lengths and loads of each branch. The load length can be found using the formula: \[ \text{Load Center Length} = \frac{(I_1 \times L_1) + (I_2 \times L_2)}{I_1 + I_2} \] Where: - \( I_1 \) and \( I_2 \) are the current for each load, - \( L_1 \) and \( L_2 \) are the respective distances. In this scenario: 1. For the first load of 20A at a distance of 60 feet: - Contribution to load center = \( 20A \times 60' = 1200 \) 2. For the second load of 50A at a distance of 125 feet: - Contribution to load center = \( 50A \times 125' = 6250 \) Next, sum the contributions: \[ \text{Total Contribution} = 1200 + 6250 = 7450 \] Now, sum the loads

To determine the load center length for a branch circuit with noncontinuous loads, it is important to calculate the weighted average based on the lengths and loads of each branch. The load length can be found using the formula:

[

\text{Load Center Length} = \frac{(I_1 \times L_1) + (I_2 \times L_2)}{I_1 + I_2}

]

Where:

  • ( I_1 ) and ( I_2 ) are the current for each load,

  • ( L_1 ) and ( L_2 ) are the respective distances.

In this scenario:

  1. For the first load of 20A at a distance of 60 feet:
  • Contribution to load center = ( 20A \times 60' = 1200 )
  1. For the second load of 50A at a distance of 125 feet:
  • Contribution to load center = ( 50A \times 125' = 6250 )

Next, sum the contributions:

[

\text{Total Contribution} = 1200 + 6250 = 7450

]

Now, sum the loads

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