What is the load center length for a branch circuit with noncontinuous loads of 125A at 80', 75A at 110', and 50A at 100'?

• A. 90'
• B. 91'
• C. 93'
• D. 95'

Answer: (C)

To determine the load center length for a branch circuit with given noncontinuous loads, one needs to find the average load length weighted by the amount of current (A) each load draws.

In this case, the loads are:

• 125A at 80'

• 75A at 110'

• 50A at 100'

First, multiply each load by its corresponding length:

• For the 125A load: 125A * 80' = 10,000 A-ft

• For the 75A load: 75A * 110' = 8,250 A-ft

• For the 50A load: 50A * 100' = 5,000 A-ft

Next, sum these products to find the total A-ft:

10,000 + 8,250 + 5,000 = 23,250 A-ft

Now, sum the total loads to find the total amperage:

125A + 75A + 50A = 250A

The load center length can then be calculated by dividing the total A-ft by the total amperage:

Load center length = Total A-ft / Total Amperage

Load center length = 23,